Question Name:Less Mark in List

Problem Description
The PDD teacher wants to know number of students got fail mark in CT I if she has a unordered list of marks for 10 students

Test Case 1
Input (stdin)
Thomas 75
Imran 60
Sithik 80
Setan 80
Milton 85
Arjun 42
Rakesh 91
Hrithik 88
Ayush 85
Aswathy 55
Expected Output
Number of the student got fail marks 1
Test Case 2
Input (stdin)
Thomas 75
Imran 60
Sithik 80
Setan 80
Milton 85
Arjun 85
Rakesh 91
Hrithik 88
Ayush 85
Aswathy 55
Expected Output
Number of the student got fail marks 0
#include <stdio.h>
int main()
{
int a[10],count=0,i;
char k[10];
for(i=0;i<10;i++)
{scanf("%s",k);
scanf("%d",&a[i]);

if(a[i]<50)
{
count++;
}
}
printf("Number of the student got fail marks %d",count);
return 0;
}
Here's a brief explanation of how the code works:
Input Handling:
The program is designed to process the marks of 10 students. For each student, the program reads the student's name (stored in k) and their corresponding mark (stored in a[i]).
Count Failures:
As each student's mark is input, the program checks if the mark is less than 50, which is considered a failing mark. If the mark is less than 50, the count variable is incremented by 1.
Output the Result:
After processing all 10 students, the program prints the total number of students who received failing marks. The result is displayed in the format: "Number of the student got fail marks X", where X is the count of failing students.
Loop Through All Students:
The loop runs 10 times, once for each student, ensuring that every student's marks are checked.
Summary: The program counts how many students received a failing mark (less than 50) from a list of 10 students and then outputs that count.